траблы с переводом совта
просто цитата от мну.
рабочий запрос
SELECT rab_info.id AS id, DATE_FORMAT(rab_info.add_date,'%d.%m.%y') AS add_date, rab_info.experience AS exp, rab_info.rubr_other AS rubr_other, rab_info.rubr_2 AS rubr_2, zrubr.name AS rubr, zrubr.parent AS parent, IF (LENGTH(rab_info.pay)>17,CONCAT(LEFT(rab_info.pay,17),'...'),rab_info.pay) AS pay, zexchange.name AS exch FROM zrubr, rab_info LEFT JOIN zexchange ON rab_info.exchange=zexchange.id INNER JOIN rab on rab.id = rab_info.rab_id INNER JOIN users ON users.id = rab.login WHERE rab_info.rubr = zrubr.id && rab_info.hidden = 'n' && users.is_agency = 'n' ORDER BY rab_info.add_date DESC
вот не...(жопа)...рабочий:
SELECT rab_info.id AS id, DATE_FORMAT(rab_info.add_date,'%d.%m.%y') AS add_date, rab_info.experience AS exp, rab_info.rubr_other AS rubr_other, rab_info.rubr_2 AS rubr_2, zrubr.name AS rubr, zrubr.parent AS parent, IF (LENGTH(rab_info.pay)>17,CONCAT(LEFT(rab_info.pay,17),'...'),rab_info.pay) AS pay, zexchange.name AS exch FROM rab_info,zrubr LEFT JOIN zexchange ON rab_info.exchange=zexchange.id INNER JOIN rab on rab.id = rab_info.rab_id INNER JOIN users ON users.id = rab.login WHERE rab_info.rubr = zrubr.id && rab_info.hidden = 'n' && users.is_agency = 'n' ORDER BY rab_info.add_date DESC
просто елки. объясните в чем траблы. в мануалах ненашел. чистое решение методом тыка
это про MySQL нерабочий работает в 4-ом
рабочий - и в 4-ом, и в 5-ом
рабочий запрос
SELECT rab_info.id AS id, DATE_FORMAT(rab_info.add_date,'%d.%m.%y') AS add_date, rab_info.experience AS exp, rab_info.rubr_other AS rubr_other, rab_info.rubr_2 AS rubr_2, zrubr.name AS rubr, zrubr.parent AS parent, IF (LENGTH(rab_info.pay)>17,CONCAT(LEFT(rab_info.pay,17),'...'),rab_info.pay) AS pay, zexchange.name AS exch FROM zrubr, rab_info LEFT JOIN zexchange ON rab_info.exchange=zexchange.id INNER JOIN rab on rab.id = rab_info.rab_id INNER JOIN users ON users.id = rab.login WHERE rab_info.rubr = zrubr.id && rab_info.hidden = 'n' && users.is_agency = 'n' ORDER BY rab_info.add_date DESC
вот не...(жопа)...рабочий:
SELECT rab_info.id AS id, DATE_FORMAT(rab_info.add_date,'%d.%m.%y') AS add_date, rab_info.experience AS exp, rab_info.rubr_other AS rubr_other, rab_info.rubr_2 AS rubr_2, zrubr.name AS rubr, zrubr.parent AS parent, IF (LENGTH(rab_info.pay)>17,CONCAT(LEFT(rab_info.pay,17),'...'),rab_info.pay) AS pay, zexchange.name AS exch FROM rab_info,zrubr LEFT JOIN zexchange ON rab_info.exchange=zexchange.id INNER JOIN rab on rab.id = rab_info.rab_id INNER JOIN users ON users.id = rab.login WHERE rab_info.rubr = zrubr.id && rab_info.hidden = 'n' && users.is_agency = 'n' ORDER BY rab_info.add_date DESC
просто елки. объясните в чем траблы. в мануалах ненашел. чистое решение методом тыка
это про MySQL нерабочий работает в 4-ом
рабочий - и в 4-ом, и в 5-ом